10125 J of heat energy boils of 4.5 g of water at $100^{\circ} C$ to steam at $100^{\circ} C$ . Find the specific latent heat of steam.

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Solution

Step 1: Given data
Heat energy $H = 10125 J$
Mass of the water $m = 4.5 g$
Step 2: Calculation of the latent heat of steam
$Heat energy = mass \times latent heat of steam H = m \times L L = \frac{H}{m} L = \frac{10125 J}{4.5 g} L = 2250 J / g$
Thus the specific latent heat of steam is 2250 J/g.

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Q. Fill in the blank spaces:

The amount of heat energy supplied to boiling water at

100^{0} C

is called latent heat of -------------- of steam.

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10125 J of heat energy boils of 4.5 g of water at 100∘Cto steam at 100∘C. Find the specific latent heat of steam.

Step 1: Given dataHeat energy H=10125JMass of the water m=4.5gStep 2: Calculation of the latent heat of steamHeatenergy=mass×latentheatofsteamH=m×LL=HmL=10125J4.5gL=2250J/gThus the specific latent heat of steam is 2250 J/g.

10125 J of heat energy boils of 4.5 g of water at $100^{\circ} C$ to steam at $100^{\circ} C$ . Find the specific latent heat of steam.

Step 1: Given data
Heat energy $H = 10125 J$
Mass of the water $m = 4.5 g$
Step 2: Calculation of the latent heat of steam
$Heat energy = mass \times latent heat of steam H = m \times L L = \frac{H}{m} L = \frac{10125 J}{4.5 g} L = 2250 J / g$
Thus the specific latent heat of steam is 2250 J/g.