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Byju's Answer

Standard XII

Physics

Latent Heat

10125 J of he...

Question

$10125 J$ of heat energy boils of $4.5 g$ of water at $100 ° C$ to steam at $100 ° C$ . Find the specific latent heat of steam.

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Solution

Step 1: Given Data and to find,
Heat Energy required to boil is $10125 J$
Weight of water is $4.5 g$
To Find: Specific Latent heat of steam
Formula Used: $Q = m L$
where $Q$ is the heat, $m$ is the mass, and $L$ is the Latent Heat
Step 2: Calculating the Latent Heat by substituting the given data in the formula
$Q = m L (10125 J) = (4.5 g) \times L L = \frac{10125 J}{4.5 g} L = 2250 J / g$
Thus, the specific latent heat of steam is $2250 J / g$

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10125J of heat energy boils of 4.5g of water at 100°C to steam at 100°C. Find the specific latent heat of steam.

$10125 J$ of heat energy boils of $4.5 g$ of water at $100 ° C$ to steam at $100 ° C$ . Find the specific latent heat of steam.