K_2SO_4⇌ 2K^++SO_4^2 #160; #160; #160; #160; 1 #160; #160; #160; #160; #160; #160; #160; 0 #160; #160; ...

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Byju's Answer

Standard XII

Chemistry

Electrolytes

17.4

Question

17.4% (w/v) $K_{2} S O_{4}$ solution at $27^{0} C$ is isotonic with 5.85% (w/v) NaCl solution at $27^{0} C$ . If NaCl is 100% ionised, what is % ionisation of $K_{2} S O_{4}$ in aq. solution?

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Solution

$K_{2} S O_{4} ⇌ 2 K^{+} + S O_{4}^{2 -}$
$1$ $0$ $0$
$1 - α$ $2 α$ $α$ $Π_{1} = \frac{w}{m . v} S . T (1 + 2 α)$
$Π_{1} = \frac{17.4 \times 1000}{174 \times 100} \times S T (1 + 2 α) = S T (1 + 2 α)$

$N a C l ⇌ N a^{+} + C l^{-}$
$1$ $0$ $0$
$1 - α_{1}$ $α_{1}$ $α_{1}$ $Π_{2} = \frac{5.85 \times 1000}{58.5 \times 100} \times S T (1 + α_{1})$
$Π_{1} = Π_{2}$ $= S T \times 2$
$\Rightarrow S T \times 2 = S T \times (1 + 2 α)$
$\Rightarrow α = {0.5}_{(g)} 50$ % ionisation of $K_{2} S O_{4}$ .

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Similar questions

17.4% (w/v) K2SO4 solution at 27°C is isotonic with 5.85% (w/v) NaCl solution at 27°C. If NaCl is 100% ionized, what is the % ionization of K2SO4 in aq. solution?

Q. 17.4% (w/V)

K_{2} S O_{4}

solution at

27^{o} C

is isotonic to 4% (w/V)

N a O H

solution at same temperature. If

N a O H

is at 100% ionised, what is the percentage of the ionisation of

K_{2} S O_{4}

in aqueous solution?

17.4 %

K_{2} S O_{4}

solution at

27^{o}

C is isotonic with

4 %

N a O H

solution at the same temperature. If

N a O H

100 %

ionised. What is the degree of ionisation of

K_{2} S O_{4}

in aq. solution?

[Note: Molarity of both the solution are equal]

Q. A 1.2% solution (w/v) of NaCl is isotonic with 7.2% solution (w/v) of glucose. Calculate degree of ionization and Van't Hoff factor of

N a C l

Q. The ratio of osmotic pressure of

0.1 M

aqueous solutions of

K_{2} S O_{4}, N a C l

i.e.

(π_{K_{2} S O_{4}} : π_{N a C l})

is:

Assume 100% ionisation, and both the solutions are at same temperature.

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17.4% (w/v) K2SO4 solution at 270C is isotonic with 5.85% (w/v) NaCl solution at 270C. If NaCl is 100% ionised, what is % ionisation of K2SO4 in aq. solution?

K2SO4⇌2K++SO2−4 1 0 0 1−α 2α α Π1=wm.vS.T(1+2α)Π1=17.4×1000174×100×ST(1+2α)=ST(1+2α)NaCl⇌Na++Cl− 1 0 01−α1 α1 α1 Π2=5.85×100058.5×100×ST(1+α1)Π1=Π2 =ST×2⇒ST×2=ST×(1+2α)⇒α=0.5(g)50% ionisation of K2SO4 .

17.4% (w/v) $K_{2} S O_{4}$ solution at $27^{0} C$ is isotonic with 5.85% (w/v) NaCl solution at $27^{0} C$ . If NaCl is 100% ionised, what is % ionisation of $K_{2} S O_{4}$ in aq. solution?