wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

25 mL of 3.0 M HNO3 is mixed with 75 mL of 4.0 M HNO3. If the volumes are additive, and 10 mL of this mixture is titrated against 2.5 M NaOH, find the volume of NaOH needed for complete neutralisation?

A
15 mL
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20 mL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
25 mL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
30 mL
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 15 mL
Dilution:
M1V1+M2V2=MfVf
3.0×25+4.0×75=Mf×100
Mf(HNO3)=3.75 M
For neutralization:
HNO3+NaOHNaNO3+H2O
(M×V×nf)HNO3=(M×V×nf)NaOH
nf is 1 for HNO3
nf is 1 for NaOH
3.75×10=2.5×VNaOH
VNaOH=15 mL

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon