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Question

3.2 moles of HI(g) were heated in a sealed bulb at 444 till the equilibrium was reached. Its degree of dissociation was found to be 20. Calculate the number of moles of hydrogen iodide, hydrogen and iodine present at the equilibrium point and determine the value of equilibrium constant for the reaction 2HI(g)H2(g)+I2(g). Considering the volume of the container 1 L.

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Solution

2HIH2+I2
At 3.2 0 0
t=0
At 3.22x 2x 2x
t=eq
x=20% of 3.2
15×3.2=0.64
1.92 1.28 1.28
Kc=1.28×1.28(1.92)2=0.444=44×102
Since volume 1 lit concentration = moles
[HI]=1.92
[H2]=1.28
[I2]=1.28
K=0.444

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