300 ml 0.1 M HCl and 200 ml of 0.03 M $H_{2}S{O}_4$ are mixed. Calculate the normality of the resulting mixture.

The correct option is A 0.084 N
For $HCl$
$V_1=300ml$
$N_1=M\times \text{Basicity}$
$=0.1\times 1=0.1$
For $H_{2}S{O}_4$
$V_2=200ml$
$N_2=M\times \text{Basicity}$
$=0.03\times 2=0.06$
Normality of the mixture,
$N=\frac{V_1{N}_1+V_2{N}_2}{V_1+V_2}$
$N=\frac{300\times 0.1+200\times 0.06}{500}$
$N=\frac{30+12}{500}=0.084N$