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Standard X

Mathematics

Solving a Quadratic Equation by Factorization Method

3x-5y=4 9x=2y...

Question

3x-5y=4

9x=2y+7;by elimination method

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Solution

Equation on rearrange
(3x -5y=4)×2
(9x-2y= 7)×5

6x-10y=8
45-10y= 35

now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.

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Similar questions

$3 x - 5 y = 4$

$9 x = 2 y + 7$
Solve the above equations by elimination method.

$3 x - 5 y = 4$
$9 x = 2 y + 7$

Solve the above equations by elimination method and find the value of x.

$3 x - 5 y = 4$
$9 x = 2 y + 7$

Solve the above equations by elimination method and find the value of x.

3 x - 5 y = 4

9 x = 2 y + 7

Solve the given equations given above using the elimination method and find the value of

x

and

y

Solve the following pair of equations by the elimination method and the substitution method:

3 x - 5 y - 4 = 0

and

9 x = 2 y + 7

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3x-5y=4

9x=2y+7;by elimination method

Equation on rearrange
(3x -5y=4)×2
(9x-2y= 7)×5

6x-10y=8
45-10y= 35

now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.

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3x-5y=4 9x=2y+7;by elimination method

Equation on rearrange (3x -5y=4)×2 (9x-2y= 7)×5 6x-10y=8 45-10y= 35 now , subtract. so , we get 39x= 27 x = 27/39 = 9/13 so , y = -5/13 ans.

COURSES

EXAMS

CLASSES

EXAM PREPARATION

RESOURCES

COMPANY

FOLLOW US

FREE TEXTBOOK SOLUTIONS

STATE BOARDS

FOLLOW US

3x-5y=4

9x=2y+7;by elimination method

Equation on rearrange
(3x -5y=4)×2
(9x-2y= 7)×5

6x-10y=8
45-10y= 35

now , subtract.
so , we get
39x= 27
x = 27/39 = 9/13
so , y = -5/13 ans.