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Laws of Mass Conservation

4 g equimolar...

Question

4 g equimolar mixture of $N a O H$ and $N a_{2} C O_{3}$ contains x g of $N a O H$ and y g of $N a_{2} C O_{3}$ .The value of x to the nearest integer (in g) is

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Solution

Total mass=4g
Now,
$m o l e s o f N a O H = m o l e s o f N a_{2} C O_{3} = a W_{N a O H} + W_{N a_{2} C O_{3}} = 4 g$
$\Rightarrow 40 a + 106 a = 4$
$\Rightarrow 40 a + 106 a = 4$
$\Rightarrow a = \frac{4}{146} m o l$
$∴ mass of NaOH = \frac{4}{146} \times 40 g = 1.095 g \approx 1 g$

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Laws of Mass Conservation

Standard XII Chemistry

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