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Addition of Vectors

8.Show that t...

Question

8.Show that the magnitude of the resultant of two vectors cannot be more than the sum of the magnitude of the two vectors.

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Solution

Dear Student,
$R = \sqrt{A^{2} + B^{2} + 2 A B \cos (θ)} H e r e m a x i m u m v a l u e o f \cos (θ) i s 1 S o R_{m a x} = \sqrt{A^{2} + B^{2} + 2 A B} = A + B$
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