96500 coulombs of charge is deposited on 1 g atom of monovalent silver. The positive charge on the silver ion is equal in magnitude to that of an electron and Avogadro's number is $6\times {10}^{23}$. The electronic charge will be

The correct option is A $-1.6\times {10}^{-19}C$

Faraday constant (i.e. charge of 96500 C) is equal to the quantity of electricity carried by one mole of charge carriers. Here, one Faraday charge deposited 1 g atom of monovalent silver, hence

$F=Ne$

where, N and e are Avogadro number and charge on a sliver ion in Coulombs respectively.

Since, the positive charge on a sliver ion is equal in magnitude to that of an electron.

$F=N(-e)$................(as electrons are negatively charged)

$-e=\frac{F}{N}$

$-e=\frac{96500}{6\times {10}^{23}}$

$-e=16083.33\times {10}^{-23}$

$e=-1.6\times {10}^{-19}C$