Factorial
Trending Questions
The value of 5! is _____
The sum of the digits in the unit place of all numbers formed with the help of taken all at a time is
- 17C10+19C11
- 17C10+19C11+17C11
- 17C10+20C11
- 19C10+19C11
In how many ways a team of 10 players out of 22 players can be made if 6 particular players are always to be included and 4 particular players are always excluded.
The number of numbers that can be formed by the digits 1, 2, 3, 4, 3, 2, 1 with the odd digits at odd places is
430
18
36
None of these
Make correct statements by filling in the symbols ⊂ or ⊄ in the blank spaces:
(i) {2, 3, 4} ..................... {1, 2, 3, 4, 5}
(ii) {a, b, c} ..................... {b, c, d}
(iii) {x : x is a student of Class XI of your school} ......... {x : x student of your school}
(iv) {x : x is a circle in the plane} ........... {x : x is a circle in the same plane with radius 1 unit}
(v) {x : x is a triangle in a plane} ........... {x : x is a rectangle in the same plane}
(vi) {x : x is an equilateral triangle in a plane} ............ {x : is a triangle in the same plane}
(vii) {x : x is an even natural number} .......... {x : x is an integer}
Find the remainder when 5k-1 is divided by 5, where k is a positive integer
(i) p : For every positive real number x the number x−1 is also positive
(ii) q : All cats scratch
(iii) r : For every real number x, either x>1 or x<1
(iv) s : There exist a number x such that 0<x<1
- 2nCn
- 21⋅62⋅103⋅⋯4n−6n−1⋅4n−2n
- n+11⋅n+22⋅n+33⋅n+44⋅⋯2n−1n−1⋅2nn
- 2n[1⋅3⋅5⋯(2n−3)(2n−1)]n!
Find the intersection of each of the following pairs of sets :
(i) X = {1, 3, 5} and Y = {1, 2, 3}
(ii) A = {a, e, i, o, u} and B = {a, b, c}
(iii) A = {x : x is a natural number and multiple of 3} and B = {x : x is a natural number less than 6}
(iv) A = {x : x is a natural number and 1 < x ≤ 6} and B = {x : is a natural number and 6 < x < 10}
(v) A = {1, 2, 3} and B=Φ
(a) r !
(b) (r − 1) !
(c) (r + 1) !
(d) none of these.
The sum of the digits in the unit place of all numbers formed with the help of 3, 4, 5, 6 taken all at a time is
18
432
108
144
- 35
- 105
- 210
- 420
- 8P4
- 8C4
- 4!×8C4
- 5!×8C5
The number of numbers that can be formed by the digits 1, 2, 3, 4, 3, 2, 1 with the odd digits at odd places is
430
36
18
None of these
The sum of the digits in the unit place of all numbers formed with the help of 3, 4, 5, 6 taken all at a time is
18
108
144
432
Eleven animals of a circus have to be placed in eleven cages one in each cage. If 4 of the cages are too small for 6 of the animals, find the number of ways of caging the animals.
The value of 2n{1.3.5.....(2n−3)(2n−1)} is
(2n)!n!
(2n)!2n
n!(2n)!
(2n−1)!n!
Find the total number of ways of selecting five letters from the letters of the word INDEPENDENT.
The number of ways in which ten candidates A1, A2, A3......A10 can be ranked if A1 and A2 are next to each other is
2!.9!
2!.8!
2!.11!
2!.10!
The sum of the digits in the unit place of all numbers formed with the help of 3, 4, 5, 6 taken all at a time is
18
108
432
144
- (n+1)!+1
- (n+1)!–1
- (n+1) !
- (n–1) !
The value of 2n{1.3.5.....(2n−3)(2n−1)} is
Eleven animals of a circus have to be placed in eleven cages one in each cage. If 4 of the cages are too small for 6 of the animals, find the number of ways of caging the animals.