Projectile Time, Height and Range
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Q. 65. Out of the following representing motion of a particle which represents SHM? 1.x=sin³ wt 2.x=1+wt+w²t² 3.x=coswt + cos3wt + cos5wt 4.x=sinwt+coswt Click here to view details:
Q. The maximum height of an oblique projectile is 8 m. The horizontal range is 24 m. The vertical component of the velocity of projection is
- √g
- 2√g
- 3√g
- 4√g
Q. A ball is projected from point A with velocity 10 m/s perpendicular to the inclined plane as shown in figure. Range of the ball on the inclined plane is equal to N3 m. Then, N is equal to
- 40
- 20
- 12
- 60
Q. A particle is projected so as to graze the top of two walls each of height 20 m. The walls are at distances of 30 m and 170 m respectively from the point of projection. Find the angle of projection.
- tan−1(23)
- tan−1(4051)
- tan−1(1)
- tan−1(45)
Q. The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m s ¯¹ can go without hitting the ceiling of the hall ?
Q. Trajectories of two projectiles are shown in figure. Let T1 and T2 be the time periods and u1 and u2 their speeds of projection. Then
- T1=T2
- T1>T2
- T1<T2
- Can not say
Q. Two bodies are thrown at angle θ and (90−θ) from the same point with same velocity 25 ms−1. If the difference between their maximum height is 15 m, find the respective maximum heights.
(g=10 ms−2)
(g=10 ms−2)
- H1=858 m and H2=1758 m
- H1=1858 m and H2=658 m
- H1=654 m and H2=1358 m
- H1=1254 m and H2=658 m
Q. A ball is thrown from a point on a ground at some angle of projection. At the same time, a bird starts from a point directly above this point of projection at a height h, horizontally with speed ′u′. Given that during its flight, the ball just touches the bird at only one point. Find the distance on the ground from the point of projection where the ball strikes.
- 2u√2hg
- 2u√hg
- u√hg
- u√h2g
Q. The trajectory of a projectile near the surface of the earth is given as y=2x−9x2. Then choose the correct option(s): [Take g=10 m/s2]
- Angle of projection is sin−1(1√5)
- Angle of projection is cos−1(1√5)
- Speed of projection is 35 m/s
- Speed of projection is 53 m/s
Q. Ratio of minimum kinetic energies of two projectiles of same mass is 4:1. The ratio of the maximum height attained by them is also 4:1. The ratio of their ranges would be
- 16:1
- 4:1
- 8:1
- 2:1
Q. The trajectory of a projectile in a vertical plane is given by y=ax−bx2, where a and b are constants and x and y are respectively horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection from the horizontal are
- b22a, tan−1(b)
- a2b, tan−1(2a)
- a24b, tan−1(a)
- 2a2b, tan−1(a)
Q. The velocity at the maximum height of a projectile is 12 times its initial velocity of projection (u). Its range on the horizontal plane is
- √3u22g
- 3u22g
- 3u2g
- u22g
Q. A ball rolls off the top of a staircase with a horizontal velocity u. If each step has a height h and a width b, then the ball will just bit the nth step, if n equals
Q. A boy standing on a long railroad car throws a ball straight upwards with a speed of 10 m/s at t=0 when the car starts moving on a horizontal road with an acceleration of 1 m/s2. How far behind the boy will the ball fall on the car? (Take g=10 m/s2).
- 4 m
- 2 m
- 4.5 m
- 8 m
Q. A man is travelling on a flatcar which is moving up a plane that is inclined at angle θ to the horizontal with a speed of 5 m/s (cosθ=45). He throws a ball towards a stationary hoop located above the incline in such a way that the ball moves parallel to the slope of the incline while going through the centre of the hoop. The centre of the hoop is 4 m high from the man's hand, perpendicular to the incline. The time taken (in seconds) by the ball to reach the hoop is [Take g=10 m/s2]
Q. An aircraft moving with a speed of 540 km/h is at a height of 6000 m, just overhead of an anti aircraft gun. If the muzzle velocity of the bullet is 300 m/s, the firing angle Q from the horizontal for the bullet to hit the aircraft should be
- 30∘
- 45∘
- 60∘
- 37∘
Q. If R and h represent the horizontal range and maximum height respectively of an oblique projectile, then R28h+2h represents
- Maximum horizontal range
- Maximum verticle range
- Time of flight
- Velocity of projectile at highest point.
Q. The ceiling of a long hall is 25 m high. What is the maximum horizontal distance that a ball thrown with a speed of 40 m/s can go without hitting the ceiling of the hall ?
Q.
Rain is falling vertically with the speed of 60 m/s. A man rides a bicycle with the speed of 20 m/s in east to west direction. What is the direction in which he should hold the umbrella?
sin-1 1/3
cos-1 1/3
tan-1 1/3
tan-1 2/3
Q. A player kicks a football at an angle of 45∘ with a velocity of 20 ms−1. A second player on the goal line 60 m away in the direction of kick starts running to receive the ball at that instant. Find the speed (m/s) of the second player with which he should run to strike the ball before it strikes the ground (g=10 ms−2)
- 2√2
- √2
- 3√2
- 5√2
Q. A fighter plane flying horizontally at an altitude of 1.5 km with speed 720 km/h passes directly overhead an anti-aircraft gun. At what angle from the vertical should the gun be fired for the shell with muzzle speed 600 ms−1 to hit the plane ? At what minimum altitude should the pilot fly the plane to avoid being hit ? (Take g=10 ms−2)
Q. Equation of trajectory of a projectile is given by y=−x2+10x where x and y are in meters and x is along horizontal and y is vertically upward and particle is projected from origin. Then which of the following options is/are correct?
(g=10 m/s2)
(g=10 m/s2)
- Initial speed of particle is √505 m/s
- Horizontal range is 10 m
- Maximum height is 25 m
- Angle of projection with horizontal is tan−1(5)
Q. The maximum height reached by projectile is 4 m. The horizontal range is 12 m. Velocity of projection in (ms−1) is
(g is acceleration due to gravity)
(g is acceleration due to gravity)
- 5 √g2
- 3 √g2
- 13 √g2
- 15 √g2
Q. A jet of water is projected at an angle θ=45∘ with the horizontal from a point which is at a distance of x=15 m from a vertical wall as shown in the figure. If the speed of projection is 10√2 m/s, find out the height from ground at which the water jet strikes vertical wall. Take g=10 m/s2
- 5 m
- 3.75 m
- 7.5 m
- 2.5 m
Q. The friction coefficient between a road and the type of a vehicle is 4/3. Find the maximum incline the road may have so that once had brakes are applied and the wheel starts skidding, the vehicle going down at a speed of 36 km/hr is stopped within 5 m.