Electrochemical Series
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Given the standard electrode potentials,
K+/K=−2.93 V, Ag+/Ag=0.80 V, Hg2+/Hg
=0.79 V
Mg2+/Mg=−2.37V.Cr3+/Cr=−0.74V
Arrange these metals in their increasing order of reducing power.
Arrange the following metals in the order in which they displace each other from the solution of their salts.
Al, Cu, Fe, Mg and Zn.
Pt2++2Cl−→Pt+Cl2, Eocell=−0.15V
Pt2++2e−→Pt, Eo=1.20V
- −1.35 V
- +1.35 V
- −1.05 V
- +1.05 V
The standard reduction potentials at 250 C of Li+ /Li , Ba2+ /Ba , Na+ /Na and Mg2+ /Mg are -3.05 , -2.73 , -2.71 and -2.37 volt respectively. Which one of the following is the strongest oxidizing agent?
Na+
Li+
Mg2+
Ba2+
- Y>Z>X
- Y>X>Z
- Z>X>Y
- X>Y>Z
Zn|Zn2+(aq), (1 M)||Fe3+(aq), Fe2+(aq)|Pt(s)
The fraction of total iron present as Fe3+ ion at the cell potential of 1.500 V is x×10−2. The value of x is :
(Nearest integer)
Given:
E0Fe3+/Fe2+=0.77 VE0Zn2+/Zn=−0.76 V
- Zinc
- Aluminium
- Magnesium
- Copper
The standard reduction potential data at 25∘C is given below.
E∘(Fe3+/Fe2+)=0.77 V;E∘(Fe2+/Fe)=−0.44V;E∘(Cu2+/Cu)=0.34 V;E∘(Cu+/Cu)=+0.52V;E∘(O2(g)+4H++4e−)→2H2O=+1.23V;E∘(O2(g)+2H2O+4e−)→4OH−=+0.40VE∘(Cr3+/Cr)=−0.74 V;E∘(Cr2+/Cr)=+0.91V
Match E∘ of the rebox pair in Column I with the values given in Column II and select the correct answer using the code given below the lists.
Column IColumn IIP.E∘(Fe3+/Fe)1.−0.18VQ.E∘(4H2O⇌4H++4OH−)2.−0.4VR.E∘(Cu2++Cu→2Cu+)3.−0.04VS.E∘(Cr3+/Cr2+)4.−0.83V
P - (4) Q - (1) R - (2) S - (3)
P - (1) Q - (2) R - (3) S - (4)
P - (3) Q - (4) R - (1) S - (2)
P - (2) Q - (3) R - (4) S - (1)
- Hg is more inert than Pt
- More voltage is required to reduce H+ at Hg than at Pt
- Na is dissolved in Hg while it does not dissolve in Pt
- Concentration of H+ ions is larger when Pt electrode is taken
Sn2++2e−→Sn, E∘=−0.14V
Hg2+2+2e−→2Hg, E∘=0.79V
Which of the following statement is correct?
- Hg can reduce Sn2+ to Sn
- Sn2+ can oxidize Hg to Hg2+2
- Hg2+2 can oxidze Sn to Sn2+
- Between Hg2+2 and Sn2+, Sn2+ is stronger oxidising agent than Hg2+2
A) N2(g)+O2(g)⟶2NO(g)
B) 2Pb(NO3)2(s)⟶2PbO(s)+4NO2(g)+O2(g)
C) NaH(s)+H2O(l)⟶NaOH(aq)+H2(g)
D) 2NO2(g)+2OH−(aq)⟶NO−2(aq)+NO−3(aq)+H2O(l)
Assertion : Copper reacts with hydrochloric acid and liberates hydrogen from the solution of dilute hydrochloric acid.
Reason : Hydrogen is present below copper in the electrochemical series.
- If both assertion and reason are true and the reason is the correct explanation of the assertion.
- If both assertion and reason are true but reason is not the correct explanation of the assertion.
- If assertion is true but reason is false.
- If the assertion and reason both are false.
E⊖ values of some redox couples are given below. On the basis of these values choose the coorect option.
E⊖ values :
Br2Br−=+1.90Ag+Ag(s)=+0.80Cu2+Cu(s)=+0.34I2(S)I−=+0.54;
(a) Cu will reduce Br−
(b) Cu will reduce Ag
(c) Cu will reduce I−
(d) Cu will reduce Br2
Write two basic requirements for refining of a metal by Mond process and by Van Arkel Method.
What is a redox reaction? Give two examples of redox reaction. Is it possible that a displacement reaction can be a redox reaction? Give examples of two redox reactions from your daily life.
The more positive the value of E⊖, the greater is the tendency of the species to get reduced. Using the standard electrode potential of redox couples given below find out which of the following is the strongest oxidising agent.
E\ominus values :
Fe3+Fe2+=+0.77I2(S)I−=+0.54;Cu2+Cu=+0.34;Ag+Ag=0.80V
(a) Fe3+
(b) I2(s)
(c) Cu2+
(d) Ag+
Arrange the following metals in the order in which they displace each other from the solution of their salts. Al, Cu, Fe, Mg and Zn.
What are chemical reactions taking place inside a lead accumulator when it supplied electric current to an external resistance?
Using the standard electrode potential, find out the pair between which redox reaction is not feasible.
E⊖values :
Fe3+Fe2+=+0.77I2I−=+0.54;Cu2+Cu=+0.34Ag+Ag=+0.80V
(a) Fe3+ and I−
(b) Ag+ and Cu
(c) Fe3+ and Cu
(d) Ag and Fe3+
Here
n1, n2 & n3 are no. of electrons exhanged in first, second and combined half cells
- E3=E1−E2
- E3=E1+E2
- E3=n1E1+n2E2n3
- E3=E1+E2n1n2n3
- It is the representation of element in order of increasing or decreasing standard electrode reduction potential
- It does not compare the relative reactivity of metals
- It compares relative strengths of oxidizing agents
- H2 is centrally placed element
Reason: Zinc is less reactive than copper.
Which of the following options are correct?
Zr and Ti are purified by van Arkel method.
Cast iron is obtained by remelting pig iron with scrap iron and coke using hot air blast.
Nickel is purified by zone refining.
In extraction of silver, silver is extracted as cationic complex.
Fe2++2e−→Fe, E∘=−0.44 V
Cu2++2e−→Cu, E∘=+0.34 V
Ag++e−→Ag, E∘=+0.80 V
I. Copper can displace iron from FeSO4 solution.
II. Iron can displace copper from CuSO4 solution.
III. Silver can displace Cu from CuSO4 solution.
IV. Iron can displace silver from AgNO3 solution.
- I and II
- II and III
- II and IV
- I and IV
Which of the following reactions is an example of auto reduction?
Can you store copper sulphate solutions in a zinc pot?