Hybridisation Involving d Orbitals
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- Bond pair-lone pair repulsion only
- Bond pair-bond pair repulsion only
- Lone pair-lone pair repulsion and bond pair- lone pair repulsion
- Lone pair-lone pair repulsion only
- dsp2 hybridization
- sp3d hybridization
- dsp3 hybridization
- sp3d2 hybridization
Describe the hybridisation in case of PCl5. Why are the axial bonds longer as compared to equatorial bonds?
Shape of the molecule having dsp2 and d2sp3 hybridisation is respectively:
Tetrahedral and Octahedral
Square planar and Trigonal bipyramidal
Octahedral and Square planar
Square planar and octahedral
- 3dx2−y2
- 3d2z
- 4dx2−y2
- 3dxy
Structure of IF+4 and hybridization of iodine in this structure are
sp3d2, Linear
sp3d2, T-shaped
sp3d, Irregular tetrahedral
sp3d2, Octahedral
- sp3
- sp3d2
- sp3d
- Both (a) and (b)
The actual geometry of is:
Planar
Linear
V-shape
Tetrahedral
- α=β=γ
- α>β>γ
- γ>β>α
- γ>α>β
- I2Cl6
- Fe2Cl4
- Solid BeCl2
- Ga2H6
- I−3
- XeF4
- XeF2
- All of the above
For , how many orbitals are possible?
- 8
- 4
- 0
- 6
- SF4
- XeF2
- ClF3
- All of the above
- PCl3
- PF2Cl3
- All of the above
- PCl5
In molecule, the lone pairs occupy equatorial positions to minimize:
Lone pair-bond pair repulsion only
Bond pair-bond pair repulsion only
Lone pair – lone pair repulsion and lone pair-bond pair repulsion
Lone pair – lone pair repulsion only
- dxy
- dx2−y2
- dz2
- dxz
- Bond pair-lone pair repulsion only
- Lone pair-lone pair repulsion and bond pair- lone pair repulsion
- Lone pair-lone pair repulsion only
- Bond pair-bond pair repulsion only
Can act as a Lewis base?
- It is sp3d hybridised and is T-shaped
- The lone pairs are located in the equatorial positions
- Its structure is analogous to SF4
- Both (A) and (C)
is linear with two lone pairs of electrons on equatorial position
- True
- False
- dx2−y2
- dz2
- dxy
- dzx
What is the Hybridization of the Central atom in ?
Is there free rotation around peptide bond?
- The axial bonds are longer than the equatorial bond
- The axial bonds are shorter than the equatorial bond
- Cl occupies the axial the bond
- none of the above
- five equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
- five equatorial lone pairs on the central I atom and two axial bonding pairs in a pentagonal bipyramidal arrangement
- three equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
- two equatorial lone pairs on the central I atom and two axial bonding pairs in a trigonal bipyramidal arrangement
- Al2(CH3)6
- I2Cl6
- Solid BeCl2
- Al2(OH)6
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The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon are respectively:
- sp, sp3, sp2
- sp, sp2, sp3
- sp3, sp2, sp
- sp2, sp, sp3