Oxidizing Nature of Sulphuric Acid
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Q.
Identify the oxidized and reduced compound in the given reaction
Q.
Match list-I with list-II
Column 1 | Column 2 |
---|---|
Hypophosphorous acid |
|
Orthophosphoric acid |
|
Hypophosphoric acid |
|
Orthophosphorous acid |
Q. The boiling points of HF, HCl, HBr and HI follows the order:
- HF>HCl>HBr>HI
- HF>HI>HBr>HCl
- HI>HBr>HCl>HF
- HCl>HF>HBr>HI
Q. In Kjeldahl's method of estimation of nitrogen, K2SO4 acts as:
- Catalytic agent
- Boiling point elevator
- Hydrolysis agent
- Oxidizing agent
Q.
Identify the oxidized and reduced substances in the following reactions.
H2(g) + Cl2(g) 2HCl(g)
Q. Arrange the following in the decreasing order of boiling point:
(i) C2H5OH
(ii) (CH3)2NH
(iii) C2H5NH2
(i) C2H5OH
(ii) (CH3)2NH
(iii) C2H5NH2
- i>ii>iii
- ii>i>iii
- i>iii>ii
- iii>ii>i
Q.
Which statement is incorrect for the reaction
CuO is reduced
is oxidized
CuO is reduced and is oxidized
Both CuO and are oxidized
Q. H2O2 has the higher boiling point than water due to stronger hydrogen bonding.
- True
- False
Q. Assign reason for the following:
(i) H3PO2 is a stronger reducing agent than H3PO4.
(ii) Sulphur shows more tendency for catenation than Oxygen.
(iii) Reducing character increases from HF to HI.
(i) H3PO2 is a stronger reducing agent than H3PO4.
(ii) Sulphur shows more tendency for catenation than Oxygen.
(iii) Reducing character increases from HF to HI.
Q. What is the correct order of boiling point?
- H2O<H2S<H2Se<H2Te
- H2O<H2Se<H2Te<H2S
- H2O>H2S>H2Se>H2Te
- H2O>H2Te>H2Se>H2S
Q. The correct order of boiling points for the given halides is:
- CCl4<CH3Cl <CH2Cl2<CHCl3
- CHCl3<CH2Cl2<CH3Cl<CCl4<
- CCl4<CHCl3<CH2Cl2<CH3Cl
- CH3Cl <CH2Cl2<CHCl3<CCl4
Q. Which one of the following has the highest bond energy?
- O−O
- S−S
- Se−Se
- Te−Te
Q. Find the oxidation state of sulphur in H2SO4.
- 6
- 4
- 3
- 2
Q. Electrolysis of H2SO4 produces _______at anode.
- H2
- O2
- H2S2O8
- H2S2O3
Q. In a mixture of concentrated H2SO4 and HNO3 intermediate formed is:
- H2SO+4
- SO2−4
- H2NO−3
- H2NO+3
Q. Assertion :Bond dissociation energy of F2 is smaller than that of Cl2. Reason: Bond dissociation energy is in order F2<Cl2<Br2<I2.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. Which reaction represents the oxidising behaviour of H2SO4?
- NaCl+H2SO4⟶NaHSO4+HCl
- 2NaOH+H2SO4⟶Na2SO4+2H2O
- 2HI+H2SO4⟶I2+SO2+2H2O
- 2PCl5+H2SO4⟶2POCl3+SO2Cl2+2HCl
Q. Which one of the following has the highest bond energy?
- Se−Se
- Te−Te
- O−O
- S−S
Q. The following is a graph plotted between the vapour pressure of two volatile liquids against their respective mole fractions. Which of the following statements are correct?


- When xA=1 and xB=0, thenP=P0A
- When xB=1 and xA=0, thenP=P0B
- When xA=1 and xB=0, thenP<P0B
- When xB=1 and xA=0, thenP>P0A
Q. The decreasing order of bond dissociation energy among halogens is:
- F−F>Cl -Cl>Br - Br >I−I
- Cl -Cl>Br - Br >F−F>I−I
- Cl -Cl>Br - Br >I−I>F−F
- I−I>F−F>Cl -Cl>Br - Br
Q. The bond order of the underlined species NOHSO4 is
Q. Which pair of compounds has the highest and the least boiling point?
- H2O, H2S
- H2O, H2Se
- H2S, H2O
- H2S, H2Se
Q. Arrange the following in the decreasing order of boiling point:
(i) C2H5OH
(ii) (CH3)2NH
(iii) C2H5NH2
(i) C2H5OH
(ii) (CH3)2NH
(iii) C2H5NH2
- iii>ii>i
- i>ii>iii
- i>iii>ii
- ii>i>iii