Banking Angle
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Take g=10 m/s2
- 20 m/s
- 30 m/s
- 15 m/s
- 25 m/s
A block is projected up to a rough plane of inclination $ 30°$. If the time of ascending is half the time for descending and the coefficient of friction is $ \mathrm{\mu } =\raisebox{1ex}{$ 3$}\!\left/ \!\raisebox{-1ex}{$5$}\right. \sqrt{\mathrm{n}} $. Then $ \mathrm{n}=$
2
The maximum speed of a car on a road–turn of radius 30 m, if the coefficient of friction between the tyres and the road is 0.4, will be
6.84 m/sec
10.84 m/sec
9.84 m/sec
8.84 m/sec
(Take g=10 m/s2)
- tan−1(23)
- tan−1(35)
- tan−1(25)
- tan−1(14)
- tanθ=√sR
- tanθ=√s2R
- tanθ=2sR
- tanθ=s2R
A cyclist riding the bicycle at a speed of 14√3ms−1 takes a turn around a circular road of radius 20√3 m without skidding. Given g=9.8ms−2, what is his inclination to the vertical
30∘
90∘
60∘
45∘
A cyclist goes round a circular path of circumference 34.3 m in √22 sec. the angle made by him, with the vertical, will be
42∘
40∘
48∘
45∘
- Up the incline
- Down the incline
- Both (a) and (b)
- None of the above
- 0.8 m
- 0.5 m
- 1 m
- 0.6 m
- [rg(cosθ+μssinθ)cosθ−μssinθ]12
- [rg(sinθ+μscosθ)cosθ−μssinθ]12
- None
- [rg(sinθ+μscosθ)cosθ+μssinθ]12
A civil engineer wishes to redesign the curved roadway in such a way that a car will not have to rely on friction to round the curve without skidding. In other words, a car moving at the designated speed can negotiate the curve even when the road is covered with ice. Such a ramp is usually banked, which means that the roadway is tilted toward the inside of the curve. Suppose the designated speed for the ramp is to be 10.0 m/s and the radius of the curve is 20.0 m. At what angle should the curve be banked?
30∘
tan−113
60∘
tan−112
- 30ms−1
- 20ms−1
- 10ms−1
- 5ms−1
A train runs along an unbanked circular track of radius 30 m at a speed of 54 km/h. The mass of the train is 106 kg. What provides the centripetal force required for this purpose - The engine or the rails? What is the angle of banking required to prevent wearing out of the rail?
- 20∘
- 45∘
- 30∘
- 60∘
A track consists of two circular parts ABC and CDE of equal radius 100 m and joined smoothly as shown in figure (7-E1). Each part subtends a right angle at its centre.A cycle weighing 100 kg together with the rider travels at a constant speed of 18 km/h on the track. (a) Find the normal contact force by the road on the cycle when it is at B and at D. (b) Find the force of friction exerted by the track on the tyres when the cycle is at B, C and D. (c) Find the normal force between the road and the cycle just before and just after the cycle crosses C. (d) What should be the minimum friction coefficient between the road and the tyre, which will ensure that the cyclist can move with constant speed ? Take g=10 m/s2.
- 80 m
- 500 m
- 800 m
- 1000 m
A cyclist taking turn bends inwards while a car passenger taking same turn is thrown outwards. The reason is
Cyclist has to counteract the centrifugal force while in the case of car only the passenger is thrown by this force
Car is heavier than cycle
Difference in the speed of the two
Car has four wheels while cycle has only two
What is the normal force in vertical circular motion?
Statement II : Centripetal force is always required for turning on a curved path.
- Both the statements I and II are incorrect.
- Statement I is incorrect and Statement II is correct.
- Both the statements I and II are correct
- Statement I is correct and Statement II is incorrect.
- 15 m/s
- 20 m/s
- 5 m/s
- 10 m/s
- tan−1(43)
- tan−1(34)
- 60∘
- tan−1(1)
- 0.2 cm
- 2 cm
- 20 cm
- None of these
- 9 m/s to 12 m/s
- 10 m/s to 20 m/s
- √188.46 m/s to √243.32 m/s
- √107.69 m/s to √657.14 m/s
Reason : The necessary centripetal force is provided by the force of friction between the tyres and the road.
Select the correct option.
- Assertion is true but the reason is false.
- Assertion and reason both are false.
- Both assertion and reason are true but the reason is not the correct explanation for the assertion.
- Both assertion and reason are true and the reason is the correct explanation for the assertion.
Obtain the answer as nearest integer value
Useful data : g=10 m/s2 , √6=2.40
- 175.5 m
- 200 m
- 170 m
- 154.3 m
- The track is not safe, 15∘
- The track is safe.
- The track is not safe, 10∘
- The track is not safe, 19∘