Buoyant Force
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A uniformly tapering vessel is filled with a liquid of density 900 kg/m3. The force that acts on the base of the vessel due to the liquid is (g=10ms−2)
3.6 N
7.2 N
14.4 N
9.0 N
- 2.6 s
- 6.2 s
- 1.3 s
- 3.1 s
- dDh
- h
- Zero
- (dD−1)h
A cubical block of side 0.5 m floats on water with 30% of its volume under water. What is the maximum weight that can be put on the block without fully submerging it under water?
[Take density of water =103 kg/m3]
- 46.3 kg
- 30.1 kg
- 87.5 kg
- 65.4 kg
- high viscosity.
- low density.
- high density.
- low viscosity.
- Both light and sound waves in air are longitudinal.
- Both light and sound waves in air are transverse.
- Both light and sound waves can travel in vacuum.
- The sound waves in air are longitudinal while the light waves are transverse.
- 4T√115
- 2T√110
- 4T√114
- 2T√114
- Zero
- Equal to the weight of the liquid displaced
- Equal to the weight of the body in air
- Equal to the weight of the immersed position of the body
- GMa2√3
- GM3a2
- GMa2[12+√2]
- 3GMa2
A fluid is flowing through a horizontal pipe of varying cross-section, with speed at a point where the pressure is . At another point where pressure is its speed is . If the density of the fluid is in and the flow is streamlined, then is equal to:
Water flows through a tube shown in figure. The areas of cross section at A and B are 1 cm2 and 0.5 cm2 respectively. The height difference between A and B is 5 cm. If the speed of water at A is 10 cm s−1, find (a) the speed at B and (b) the difference in pressures at A and B.
- 10.4 cm
- 8.4 cm
- 6.4 cm
- 5.4 cm
Take g=10 ms−1
- 18.7 N
- 27.6 N
- 42.5 N
- 32.7 N
- 34
- 23
- 12
- 14
In a simple Atwood machine, two unequal masses m1 and m2 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (Figure) m1=300 g and m2=600g. The system is released from rest. (a) Find the distance travelled by the first block in the first two seconds. (b) Find the tension in the string. (c) Find the force exerted by the clamp on the pulley.
- √78T
- √58T
- √38T
- √87T
- T
- (910)T
- T√109
- √9T10
- 1 notwen=6.67×10−11 newton
- 1 notwen=6.67×10−19 newton
- 1 notwen=6.67×10−12 newton
- 1 notwen=6.67×10−17 newton
- 6000 kg/m3
- 5000 kg/m3
- 4000 kg/m3
- 7000 kg/m3
- 7.5 R
- 7 R
- 6 R
- 8.5 R
The sound carried by air from a sitar to a listener is a wave of which of the following type:
Longitudinal stationary
Transverse progressive
Transverse stationary
Longitudinal progressive
Given: Density of iron =7800 kg/m3, density of wood =800 kg/m3 and density of air =1.293 kg/m3
- 1.5
- 2.0015
- 1.0015
- 3.0015
- 1+rRE+r2R2E+r3R3E
- 1+rRE−r2R2E−r3R3E
- 1−rRE−r2R2E−r3R3E
- 1+rRE−r2R2E+r3R3E
A length of the string has a mass of . if the tension in the string is , the speed of a wave on the string is
- 10 N, 32×10−3 m3
- 20 N, 32×10−3 m3
- 20 N, 16×10−3 m3
- 10 N, 16×10−3 m3
- 3840 kg/m3
- 2040 kg/m3
- 2540 kg/m3
- 4838 kg/m3
- The tension in the string is 40 N.
- The tension in the string is 120 N.
- The volume of the rod is 6.4×10−2 m3.
- The point of action of the buoyant force is C (centre of mass of rod).
Two large glass plates are placed vertically and parallel to each other inside a tank of water with separation between the plates equal to 1 mm. find the rise of water in the space between the plates. Surface tension of water = 0.075 N m-1.
1.5 mm
15 cm
1.5 cm
0.015 cm
- 36 N
- 60 N
- 44 N
- 56 N