Phase and the General Equation
Trending Questions
Q. Two particles execute SHM of the same amplitude and frequency along the same straight line. They pass one another when going in opposite directions each time their displacement is half their amplitude. What is the phase difference between them?
- 60∘
- 30∘
- 90∘
- 120∘
Q. Two particles P and Q describe SHM of same amplitude A, same frequency f along the same straight line. The maximum distance between the two particles is A√2. The phase difference between the particle is
- Zero
- π3
- π2
- π6
Q. A particle executes simple harmonic oscillation with an amplitude A. If the time period of oscillation is T, then minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
- T2
- T4
- T12
- T8
Q. A particle executes simple harmonic motion between x = -A and x = +A. The time taken for it to go from 0 to A/2 is T1 and to go from A/2 to A is T2. Then
- T1<T2
- T1>T2
- T1=T2
- T1=2T2
Q. A particle executing S.H.M. of amplitude 4 cm and T=4 sec. The time taken by it to move from positive extreme position(+a) to half the amplitude is
- 1 sec
- 1/3 sec
- 2/3 sec
- √3/2 sec
Q.
Two bodies performing S.H.M. have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is
- π
- π3
- 35π
- 116π
Q. If vectors →A=coswt^i+sinwt^j and →B=coswt/2^i+sinwt/2^j are functions of time , then the value of t at which they are orthogonal to each other is
- t=π2ω
- t=πω
- t=0
- t=π4ω
Q. A particle is performing simple harmonic motion along x− axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x=+2 cm to x=+4 cm and back again is given by
- 0.6 sec
- 0.4 sec
- 0.3 sec
- 0.2 sec
Q.
A particle performs simple harmonic motion with a period of . The time taken by the particle to cover a displacement equal to half of its amplitude from the mean position is . The value of ‘’ to the nearest integer is _____.
Q. A particle is executing simple harmonic motion, Its displacement is given by x=5 sin πt, where x is in cm and t in seconds. How long will the particle take to move from the position of equilibrium to the position of maximum displacement?
- 0.5 s
- 1.0 s
- 1.5 s
- 2.0 s
Q. Starting from rest, a particle rotates in a circle of radius R=√2m with an angular acceleration α=π4rad/s2. Average velocity (in m/s) of the particle over the time it rotates quarter circle.
Q. The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is
Q. A particle moves on the X-axis according to the equation x=A+Bsinω t. The motion is simple harmonic with amplitude.
A
B
A+B
Q. A particle executes SHM with a period of T second and amplitude A metre. The particle is at its mean position initially The shortest time it takes to reach point A√2 metre from its mean position in seconds is
- T
- T4
- T8
- T16
Q.
A particle is subjected to two simple harmonic motions in the same direction having equal amplitudes and equal frequency. If the resultant amplitude is equal to the amplitude of the individual motions, find the phase difference between the individual motions.
0