Second Law of Motion
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(g=10 ms−2)
- 12 Kg
- 13 Kg
- 16 Kg
- 112 Kg
- F2
- F4
- F8
- F16
A parachutist with total weight 75 kg drops vertically onto a sandy ground with a speed of 2 ms−1 and comes to a halt over a distance of 0.25m. The average force from the ground on her is close to.
600 N
1200 N
1350 N
1950 N
- 15, 5
- 10, 10
- 35, −15
- 25, −5
A body of mass 2kg is moving with an acceleration of 50cm s^-1 calculate the force acting
- 30 N
- 0 N
- 20 N
- 10 N
[Take g=10 m/s2]
- 11.5 m
- 20.15 m
- 31.25 m
- 5.75 m
- 1√2γgtan−1(√2γgv0)
- 1√γgtan−1(√γgv0)
- 1√γgln(1+√γgv0)
- 1√γgsin−1(√γgv0)
A ball of mass (m) 0.5 kg is attached to the end of a string having length (l) 0.5m. The ball is rotated on a horizontal circular path about vertical axis. The maximum tension that the string can bear is 324 N. The maximum possible value of angular velocity of ball (in rad/s) is
9
18
27
36
Explain why some of the leaves may get detached from a tree if we vigorously shake its branch.
If the net force acting on a body be zero, then will the body remain necessarily in rest position?
- 5 m/s2
- 25 m/s2
- 10 m/s2
- 2.5 m/s2
[g=9.8 m/s2; sin30∘=12; cos30∘=√32]
- 2.3 s
- 0.46 s
- 1.3 s
- 0.92 s
What is momentum? Explain with examples.
- 45∘
- 90∘
- 0∘
- 30∘
- iLB2π
- iL2Bπ
- iL2B4π2
- iL2B2π
- 0.02
- 0.06
- 0.01
- 0.03
- 60 kg
- 30 kg
- None of these
- 120 kg
- 1 N
- 2 N
- 4 N
- 5 N
- 1.8 kg
- 1.0 kg
- 1.2 kg
- 1.5 kg
A motorcar of mass kg is moving along a straight line with a uniform velocity of km/h. Its velocity is slowed down to km/h in s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required?
- 120 N
- 160 N
- 200 N
- 40 N