Work Done: Spring
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A long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be
A spring of force constant 800 N/m has an extension of 5 cm. The work done in extending it from 5 cm to 15 cm is
16 J
8 J
24 J
32 J
The potential energy of a certain spring when stretched through a distance 'S' is 10 joule. The amount of work (in joule) that must be done on this spring to stretch it through an additional distance 'S' will be
30
40
10
20
A spring 40 mm long is stretched by the application of a force. If 10 N force required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is
68 J
84 J
23 J
8 J
A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is g=9.8 m/sec2
- 490 Joules
+ 980 Joules
+ 490 Joules
- 980 Joules
- More work is done on B, i.e., WB>WA
- More work is done on A, i.e., WA>WB
- Work done on A and B are equal
- Work done depends on the way in which they are stretched
- 0.15 J
- 0.3 J
- 0.45 J
- None
In the figure ball A is released from rest, when the spring is at its natural length. For the block B of mass M to leave contact with the ground at some stage, the minimum mass of A must be
2 M
M
A function of M and force constant of spring
M2
- 6.0 m
- 12.0 m
- 10.0 m
- 8.0 m
The force constant of a wire is k and that of another wire is 2k. When both the wires are stretched through same distance, then the work done
A body of mass 10 kg is dropped to the ground from a height of 10 metres. The work done by the gravitational force is g=9.8 m/sec2
- 490 Joules
+ 490 Joules
- 980 Joules
+ 980 Joules
A spring when stretched by 2 mm its potential energy becomes 4 J. If it is stretched by 10 mm, its potential energy is equal to
54 J
415 J
None
4 J
- 2.5kx2
- 1.5kx2
- −3.5kx2
- 3.5kx2
- Work done by force F is equal to
- Increases in energy stored in spring is
- equal in both
- greater for the longer part
- greater for the shorter part
- data insufficient

Two springs have their force constant as k1 and k2(k1>k2) . When they are stretched by the same force
More work is done in case of second spring
Equal work is done in case of both the springs
No work is done in case of both the springs
More work is done in case of first spring
A long spring is stretched by applying a force. If force is required to stretch the spring through one mm, then work done in stretching the spring through is:
- the resulting motion is uniform circular motion.
- the resulting motion is a linear simple harmonic motion along a straight line inclined equally to the straight lines of motion of component ones.
- the resulting motion is an elliptical motion, symmetrical about the lines of motion of the components.
- the two S.H.M. will cancel each other.
- F
- 2F
- F2
- F2
Two springs of spring constants and respectively are stretched with the same force. They will have potential energy in the ratio:
What type of work is done in stretching a Spring?
- 1.5 Joule
- 2.0 Joule
- 2.5 Joule
- 3.0 Joule
The potential energy of the spring when stretched ______.
If the force constant of a wire is K, the work done in increasing the length of the wire by l is
Kl/2
Kl