A(0, 0), B(6, 0), C(4, 2), D(2, 2) are the vertices of trapezium ABCD.

E and F are the midpoints of AD and BC respectively then, EF =?.

Q.

In a trapezium ABCD, E and F be the midpoints of the diagonals AC and BD respectively. Then, EF = ?

(a) $\frac{1}{2}AB$

(b) $\frac{1}{2}CD$

(c) $\frac{1}{2}(AB+CD)$

(d) $\frac{1}{2}(AB-CD)$

Q. $E$ and $F$ are respectively the midpoint of non-parallel sides $AD$ and $BC$ of a trapezium $ABCD$, prove that $EF$ $||ABandEF=\frac{1}{2}(AB+CD)$

Q. Question 12
E and F are respectively the mid-points of the non-parallel sides AD and BC of a trapezium ABCD, Prove that $EF||ABandEF=\frac{1}{2}(AB+CD)$.

Q. E and F are respectively the midpoints of non-parallel sides $AD,BC$ of a trapezium $ABCD$. Prove that $EF||AB$

Q. abcd is a trapezium in which abIIcd , e is the midpoint of side ad. if f is a point on side bc such that efIIcd, prove that f is midpoint of bc and ef= 1/2(ab+cd)