A $10 %$ solution is one in which 10 gm of solute is dissolved in 100 gm of water. On heating the solution water evaporates. So, 1 kg of the $10 %$ solution is reduced to 0.4 kg. What is its concentration now?

32.6%

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14.8%

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22.7%

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29.4%

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Solution

The correct option is D 29.4%
In a $10 %$ solution, in 110 gm of solution there is 10gm of solute.

So, 1 kg of solution has $1 \times \frac{10}{110} = \frac{1}{11}$ kg of solute.

After heating, amount of solution = 0.4 kg

So, amount of water $= \frac{2}{5} - \frac{1}{11} = \frac{17}{55}$ kg

Solution percentage $= (\frac{1}{11}) \times (\frac{55}{17}) \times 100 = 29.4 %$

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