A 300 m long train is moving with a uniform velocity of 90 km/hr. The time taken by the train to cross a bridge of length 1700 m is:

56 s

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68 s

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80 s

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92 s

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Solution

The correct option is C 80 s
Distance to cover $= (300 + 1700) m$
$t = \frac{2000}{\frac{90 \times 5}{18}} = 80 s e c .$

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