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Heat of Reaction

A 4:1 mixture...

Question

A 4:1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is:

A

8 : 1

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B

8 : 3

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C

4 : 1

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D

1 : 1

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Solution

The correct option is A 8 : 1
Pressure of helium = 8 bar $C H_{4} = 2 bar$
According to Graham's law
$\frac{r_{1}}{r_{2}} = \frac{P_{1}}{P_{2}} \sqrt{\frac{M_{2}}{M_{1}}}$
$\frac{r_{H e}}{r_{C H_{4}}} = \frac{P_{H e}}{P_{C H_{4}}} \sqrt{\frac{M_{C H_{4}}}{M_{H e}}}$
$\frac{r_{H e}}{r_{C H_{4}}} = \frac{8}{2} \sqrt{\frac{16}{4}} = \frac{8}{1} = 8 : 1$

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