A astronomical telescope has objective and eyepiece of focal lengths 40cm and 4cm respectively. To view an object 200cm away from the objective, the lenses must be separated by a distance
A
46cm
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B
54cm
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C
50cm
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D
37.3cm
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Solution
The correct option is B54cm Given: fo=40cm,fe=4cm
Tube length (l)= Distance between lenses l=v0+fe
For objective lens, uo=−200cm,v0= ? 1v0−1u0=1f0
or 1v0−1−200=140 or1v0=140−1200=4200 ∴v0=50cm ∴l=50+4=54cm
Hence , option (B) is correct.