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Byju's Answer
Standard VII
Mathematics
Integers
a, b, c, d, e...
Question
a
,
b
,
c
,
d
,
e
are five integers such that
a
+
b
=
b
+
c
=
c
+
d
=
d
+
e
=
2015
,
a
+
b
+
c
+
d
+
e
=
5030
, then
(
d
−
a
)
is
A
12
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B
15
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C
18
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D
0
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Solution
The correct option is
B
15
Consider the equation,
a
+
b
=
b
+
c
=
c
+
d
=
d
+
e
=
2015
(Given)
a
+
b
+
c
+
d
+
e
=
5030
(Given)
Now,
(
a
+
b
)
+
(
b
+
c
)
+
(
c
+
d
)
+
(
d
+
e
)
=
2015
+
2015
+
2015
+
2015
a
+
2
b
+
2
c
+
2
d
+
e
=
8060
a
+
b
+
c
+
d
+
e
=
5030
substitute in the above expression,
b
+
c
+
d
=
3030
d
=
1015
a
+
2
(
b
+
c
)
+
d
+
d
+
e
=
8060
a
+
4030
+
1015
+
2015
=
8060
a
=
8060
−
7060
a
=
1000
d
−
a
=
1015
−
1000
d
−
a
=
15
Hence,
d
−
a
=
15
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0
Similar questions
Q.
if a , b , c , d , e are distinct integers such that (8 - a )(8 - b)(8 - c)(8 - d)(8 - e) = 12 , then find a+b+c+d+e
Q.
In
∆ABC, BD ⊥ AC
and CE
⊥ AB such that BE = CD. Prove that BD = CE.