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Question

A ball is dropped from a building of height 45 m. simultaneously another ball is thrown up with a speed 4m/s. Calculate the relative speed of the balls as a function of time

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Solution

Hint: Motion under gravity.

in motion under gravity, if a body is released or dropped, that means its initial velocity is zero. Both balls are freeely falling. Hence, there is no acceleration of one with respect to another.

Therefore, relative speed remains constant (=40m/s)

Final answer:

=40m/s

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