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Question
A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground, how much high can the ball bounce back? (g=10 ms−2)
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Solution
Given,
h = 10m
g=10 ms−2
E=W=mgh=m×10×10=100mJ.
Energy is reduced by 40% then the remaining energy is 60 mJ.
Therefore, 60m=m×10×h′ or h′=6m
h = 10m
g=10 ms−2
E=W=mgh=m×10×10=100mJ.
Energy is reduced by 40% then the remaining energy is 60 mJ.
Therefore, 60m=m×10×h′ or h′=6m
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