A ball is dropped from the top of a building. The ball takes 0.5 s to fall past the 3 m length of a window at certain distance from the top of the building. Time of travel above the window is (Take g=10m/s2)
A
0.5 s
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B
0.25 s
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C
0.35 s
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D
0.75 s
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Solution
The correct option is C 0.35 s s=ut+12gt2 3=u(0.5)+12×10(0.5)2 3=(0.5)u+5(0.25) 1.750.5=u ⇒u=3.5m/s