A ball is projected from a point on an inclined plane horizontally. It takes $\frac{1}{\sqrt{2}}$ seconds to strike the plane. If the incline plane makes an angle of ${30}^{\circ }$ with horizontal, then find the range of the ball on incline plane in meters. [g = 10 $m/s^2$] ___

Q. An inclined plane makes as angle ${\theta }_0={30}^{\circ }$ with the horizontal. A particle is projected from this plane with a speed of $5\text{m/s}$ at an angle of elevation $\beta ={30}^{\circ }$ with the horizontal as shown in the figure.


Find the range of the particle on the plane when it strikes the plane. (Assume the incline is long enough and $g=10{\text{m/s}}^2$)

Q. An inclined plane makes as angle ${\theta }_0={30}^{\circ }$ with the horizontal. A particle is projected from this plane with a speed of $5\text{m/s}$ at an angle of elevation $\beta ={30}^{\circ }$ with the horizontal as shown in the figure.


Find the range of the particle on the plane when it strikes the plane. (Assume the incline is long enough and $g=10{\text{m/s}}^2$)

Q. An inclined plane is making an angle $\beta$ with horizontal. A projectile is projected from the bottom of the plane with a speed $u$ at an angle $\alpha$ with horizontal then its range $R$ when it strikes the inclined plane is :

Q. On an inclined plane of inclination ${30}^{\circ }$, a ball is thrown at an angle of ${60}^{\circ }$ with the horizontal, from the foot of the incline, with a velocity of $10\sqrt{3}{\text{ms}}^{-1}$. Then, the ball will hit the inclined plane in time: (take $g=10m{s}^{-2}$)

Q. A particle is projected with some velocity $u$ making an angle ${60}^0$ with horizontal up an inclined plane. The plane makes an angle ${30}^0$ with horizontal. The particle's range on the inclined plane with it's time of flight $T$, is :