A ball is rolled off the edge of a horizontal table at a speed of 4 m/second. It hits the ground after 0.4 second. Which statement given below is true

The correct options are
A

It hits the ground at a horizontal distance 1.6 m from the edge of the table

C

Height of the table is 0.8 m

(a,c)Vertical component of velocity of ball at point P
$V_v$ =0+gt=10$\times$0.4=4m/s
Horizontal component of velocity = initial velocity
$\Rightarrow$$V_H$ = 4m/s

So the speed with which it hits the ground
v = $\sqrt{v_R^2+v_v^2}$ = 4$\sqrt{2}$m/s
and tan$\theta$ = $\frac{V_r}{V_H}$ = $\frac{4}{4}$ = 1$\Rightarrow$ $\theta$ = ${45}^{\circ }$
It means the ball hits the ground at an angle of ${45}^{\circ }$ to the horizontal.
Height of the table
h = $\frac{1}{2}$g$t^2$ = $\frac{1}{2}$$\times$10$\times$$(0.4{)}^2$ = 0.8m
Horizontal distance traveled by the ball from the edge of table h = ut = 4 $\times$ 0.4 = 1.6m