A ball is thrown vertically upwards with a speed $v$ from a height $h$ metre above the ground. The time taken for the ball to hit ground is

Q. A person standing near the edge of the top of a building throws two balls $A$ and $B$. The ball $A$ is thrown vertically upwards and $B$ is thrown vertically downward with the same speed. The ball $A$ hits the ground with a speed $v_A$ and the ball $B$ hits the ground with a speed $v_B$. Then,

Q. A ball is thrown vertically upward from a height of $40\text{m}$ and hits the ground with a speed that is three times it's initial speed. What is the time taken (in sec.) for the fall?

Q. A person standing near the edge of the top of a building throws two balls $A$ and $B$. The ball $A$ is thrown vertically upward and $B$ is thrown vertically downward with the same speed. The ball $A$ hits the ground with a speed $v_A$ and the ball $B$ hits the ground with a speed $v_B$. We have: