A ball is thrown vertically upwards with a velocity of $30m{s}^{–1}$ What will be the height reached by the body at the end of $4s$ (consider $g$ $10m{s}^{–2}$)?

The correct option is D

$40m$

Step 1: Given data and formula used

$u=30m{s}^{–1}t=4s;a=–g=–10m{s}^{–2}$

Formula used:

$h=ut+\frac{1}{2}a{t}^2$

Step 2: Calculation of the height

$h=30\times 4-\frac{1}{2}\times 10\times 16=120–80=40m$
Hence, the correct option is (d).