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Question

A ball is thrown with a velocity of 8 ms1 making an angle of 60o with the horizontal. It's velocity will be perpendicular to the direction of initial velocity of projection after a time of (g=10ms2)

A
1.63s
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B
43s
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C
43s
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D
0.83s
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Solution

The correct option is A 1.63s
u(t)=vcos60^i+(vsin60gt)^j
u(o)=vcos60^i+vsin60^j
At time t:
u(t)u(0)=0 for these to be
(vcos60)2+(vsin60)2vsin60gt=0
v2=vsin60gt
t=vg23=8×2g3=1610×33=1.63s

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