A ball is thrown with an initial velocity of $20\frac{m}{s}$. Find the time of flight and the maximum height reached by the body. $(g=10\frac{m}{s^2}$)

The correct option is A

4 s and 20 m

Since acceleration due to gravity is opposite to the motion. At some point of motion, velocity will become zero. At that moment, the ball will change the direction of motion and fall downwards. Thus at maximum height, velocity will be zero.
Since, acceleration of gravity is opposite to motion, a = -10 m/s²

Initial Velocity $u=20\frac{m}{s}$

Velocity at maximum height $v=0$

From, v = u + at
0 = 20+ (-10) t
t = 2 s
Thus the ball takes 2 s to reach the top. Similarly to reach the ground from the top point is also 2 s. Thus total time or time of flight is 4 s.
$s=ut+\frac{1}{2}a{t}^2$​
$s=20\times 2+\frac{1}{2}\times (-10)\times 2^2=20m$