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Question

A ball moving with velocity 2 m/s, collides head-on with another stationary ball of double the mass. If the coefficient of restitution is 0.5, then their velocities (in m/s) after collision will be:

A
0,2
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B
0,1
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C
1,1
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D
1,0.5
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Solution

The correct option is B 0,1

Hint: “Conservation of momentum”

Formula used:

Pi=Pf

e=velocity of seperationvelocity of approach

Solution:

Conservation of momentum,

m×2+2m×0=mv1+2mv2

v1+2v2=2 (i)

v1v2=e(u1u2)

e(20)=12(2)=1 (ii)

Solving v1=0,

v2=1 m/s

Final Answer: (b).

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