A ball of weight $0.1$ kg coming with a speed $30$ m/s strikes a bat and returns in opposite direction with speed of $40$ m/s, then impulse is

- 0.1 \times 40 - 0.1 \times 30 N s

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0.1 \times 40 - 0.1 \times (- 30) N s

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0.1 \times 40 + 0.1 \times (- 30) N s

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0.1 \times 40 - 0.1 \times 20 N s

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Solution

The correct option is B $0.1 \times 40 - 0.1 \times (- 30) N s$
Given,
$m = 0.1 k g$
$u = 30 m / s$
$v = - 40 m / s$
Impulse = change in momentum
$m v_{2} - m v_{1} = 0.1 \times 40 - 0.1 \times (- 30)$
The correct option is B

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