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Question

A ballet dancer is rotating at an angular velocity ω on smooth horizontal floor. The ballet dancer folds his body close to his axis of rotation by which his radius of gyration decreases by 14 th of his initial radius of gyration. His final angular velocity is:

A
3ω4
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B
9ω4
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C
9ω16
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D
16ω9
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Solution

The correct option is D 16ω9
ConservingangularmomentumI1ω=I2ωmK21ω=mK22ωK21ω=(3K14)2ωω=169ω

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