36
Question
A block of mass 1 kg is resting over a rough inclined plane and a force F of magnitude 2 N is applied vertically upward as shown in figure, then magnitude of net contact force (in N) on the block by the inclined plane will be
F=2N
Rough surface i l
g
<37
F=2N Rough surface i l g <37
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Solution
F.B.D
Since block is at rest
(\Rightarrow \vec {F_C}+\vec {F}+m\vec {g}=0\)
⇒→FC=8 N^j
Since block is at rest
(\Rightarrow \vec {F_C}+\vec {F}+m\vec {g}=0\)
⇒→FC=8 N^j
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