A block of mass (m=1kg) is released from rest over a circular curved path, as shown in diagram. The work done (in joules) by normal force, when block is displaced by θ=45∘ is
A
0.0
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B
0.00
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C
00
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D
0
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Solution
Normal force is always perpendicular to surface of contact and displacement is along surface of contact.
So, the angle between normal force and displacement is 90∘
Work done by normal force is W=Ndcosθ W=Ndcos90∘=0