A block slides down a smooth inclined plane when released from the top, while another falls freely from the same point. Which one of them will strike the ground: (a) earlier (b) with greater speed?

Q. A block slides down a smooth inclined plane to the ground when released at the top, in time $tsec$. Another block is dropped vertically from the same point in the absence of the inclined plane and reaches the ground in $t/2sec$. Then the angle of the inclination of the plane with the vertical is:

Q. A man slides freely down a frictionless inclined plane while his bag falls down vertically from the same height. The final speeds of the man $\left(v_M\right)$ and the bag $\left(v_B\right)$ should be such that:

Q. Assertion :A ball of mass $m$ is released from the top of a smooth inclined plane. At the same time another ball of same mass allowed to fall freely from same height. When both balls reaches the bottom of the plane, momentum will not be equal. Reason: Momentum depends on the direction of velocity as well as its magnitude.

Q. A block of mass $m$ is freely sliding down on a smooth inclined plane from its top. The block reaches the bottom of inclined plane and then describes a vertical circle of radius $r$ along smooth track. If vertical height of inclined plane is $3r$, the normal reaction on the block when it is crossing highest point of vertical circle:

Q. A wooden block sliding down from the top of a smooth inclined plane starting from rest takes $t_1$ seconds to reach the bottom of the plane and attains velocity $v_1$. Another block of twice the mass falling freely in air from the same height takes $t_2$ seconds to reach the bottom of the plane and attains velocity $v_2$. If the angle of inclination of the plane is ${30}^0$, then