A boat man could row his boat with a speed 10 m - sec- He wants to take his boat from P to a point Q just opposite on the other bank of the river flowing at a speed 4 m - sec- He should row his boat-A- At right angle to the streamB- At an angle of sin -12-5 with P Q down the streamC- At an angle of cos -12-5 with P Q down the streamD- At an angle of sin -12-5 with P Q up the stream

Let v_b be the velocity of the boat w.r.t. the river nbsp; sin θ = v_sv_b θ =sin^ 1 ( 410 ) θ = sin^ 1 ( 25 ) with PQ up the stream. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Relative Velocity in 2D

A boat man co...

Question

A boat man could row his boat with a speed $10 m/sec$ . He wants to take his boat from $P$ to a point $Q$ just opposite on the other bank of the river flowing at a speed $4 m/sec$ . He should row his boat–

At right angle to the stream

No worries! We‘ve got your back. Try BYJU‘S free classes today!

At an angle of

{sin}^{- 1} (\frac{2}{5})

with

P Q

up the stream

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

At an angle of

{sin}^{- 1} (\frac{2}{5})

with

P Q

down the stream

No worries! We‘ve got your back. Try BYJU‘S free classes today!

At an angle of

{cos}^{- 1} (\frac{2}{5})

with

P Q

down the stream

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B At an angle of ${sin}^{- 1} (\frac{2}{5})$ with $P Q$ up the stream

Let $v_{b}$ be the velocity of the boat w.r.t. the river
$sin θ = \frac{v_{s}}{v_{b}}$
$θ = {sin}^{- 1} (\frac{4}{10})$
$θ = {sin}^{- 1} (\frac{2}{5})$ with $P Q$ up the stream.

Suggest Corrections

Similar questions

Q. A boat man could row his boat with a speed

10 m/sec

. He wants to take his boat from

P

to a point

Q

just opposite on the other bank of the river flowing at a speed

4 m/sec

. He should row his boat–

Q. A man wants to cross the river to an exactly opposite point on the other bank. If he can row his boat with twice the velocity of the current, then at what angle to the current he must keep the boat pointed?

Q. A man wants to cross the river to an exactly opposite point on the other bank. If he can row his boat with

\frac{2}{\sqrt{3}}

times the velocity of the current, then at what angle to the current he must keep the boat pointed ?

Q. Given

∣ ∣ ∣ {\to V}_{b r} ∣ ∣ ∣ = 4 m / s

=magnitude of velocity of boatman with respect to river,

{\to V}_{r} = 2 m / s

in the direction perpendicular to velocity of boatman. Boatman wants to reach from point A to point B. At what angle

θ

should he row his boat? Assume that B is nearest point to A on the far bank.

Q. A man can row a boat at

4 km/h

in still water. If he is crossing a river which is

4 km

wide, and the speed of current is

2 km/h

, then in what direction should his boat be headed if he wants to reach a point on the other bank, directly opposite to the starting point?

Join BYJU'S Learning Program

A boat man could row his boat with a speed 10 m/sec. He wants to take his boat from P to a point Q just opposite on the other bank of the river flowing at a speed 4 m/sec. He should row his boat–

The correct option is B At an angle of sin–1(25) with PQ up the stream Let vb be the velocity of the boat w.r.t. the river sin θ=vsvb θ=sin−1(410) θ=sin−1(25) with PQ up the stream.

A boat man could row his boat with a speed $10 m/sec$ . He wants to take his boat from $P$ to a point $Q$ just opposite on the other bank of the river flowing at a speed $4 m/sec$ . He should row his boat–

The correct option is B At an angle of ${sin}^{- 1} (\frac{2}{5})$ with $P Q$ up the stream

Let $v_{b}$ be the velocity of the boat w.r.t. the river
$sin θ = \frac{v_{s}}{v_{b}}$
$θ = {sin}^{- 1} (\frac{4}{10})$
$θ = {sin}^{- 1} (\frac{2}{5})$ with $P Q$ up the stream.