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Question

A bob of mass 0.1 kg hung from the ceiling of a room by a string 2 m long is set into oscillation. The speed of the bob at its mean position is 1 m s1. What is the trajectory of the bob if the string is cut when the bob is

A at one of its extreme positions

B at its mean position

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Solution

Free fall of body in vertical direction

At the extreme position, the velocity of the bob becomes zero. If the string is cut at this moment, then the bob will fall vertically downwards, just like under free fall.


Applying Newton’s second equation of motion in vertical direction

At the mean position, the velocity of bob is 1 m s1 in the horizontal direction; then it will trace a projectile path having constant horizontal velocity i.e., 1 m s1. under the influence of gravity which is acting vertically downward.

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