A body centred cubic lattice is made up of hollow spheres of B. Spheres of solid A are present inside the hollow spheres of B. If the radius of A is half the radius of B, what is the ratio of the total volume of spheres of B unoccupied by A in a unit cell and the volume of the unit cell?

Q. A body centred cubic lattice is made up of hollow spheres of $B$. Spheres of solid $A$ are present in hollow spheres of $B$. Radius of $A$ is half of radius of $B$. What is the ratio of total volume of spheres of $B$ unoccupied by $A$ in a unit cell and volume of unit cell?

Q. A body centered cubic lattice is made up of hollow spheres of B. Spheres of solid A are present in hollow spheres of B. Radius A is half of radius of B. What is the ratio of total volume of spheres of B unoccupied by A in a unit cell and volume of unit cell?

Q. A body centered cubic lattice is made up of hollow shere of $B$. Sphere of solid $A$ are present in hollow sphere of $B$. Radius of $A$ is half of the radius of $B$. What is the ratio of total volume of sphere $B$ unoccupied by $A$ in unit cell and volume of unit cell?

Q. A bcc lattice is made up of hollow spheres of B. Spheres of solids A are present in hollow spheres of B. The radius of A is half of the radius of B. The ratio of total volume of spheres of B unoccupied by A in a unit cell and volume of unit cell is A$\times \frac{\pi \sqrt{3}}{64}$. Find the value of A.

Q. At ${1425}^{\circ }C,Fe$ crystallises in a body-centred cubic lattice whose edge length is $2.93\stackrel{\circ }{A}$. Assuming the atoms to be packed spheres, calculate:
(a) the radius of the spheres,
(b) the distance between centres of neighbouring spheres,
(c) the number of atoms of $Fe$ per unit lattice and
(d) the total volume occupied by an atom of $Fe$.