A body executing SHM has a total energy E. When its kinetic energy is $\frac{3E}{4}$ , the displacement of the particle is ( a is amplitude ):

Q. A particle starts executing simple harmonic motion $\left(\text{SHM}\right)$ of amplitude ${}^{\prime }{a}^{\prime }$ and total energy $E$. At any instant, its kinetic energy is $\frac{3E}{4}$ then its displacement ${}^{\prime }{y}^{\prime }$ is given by :

Q.

A particle starts executing S.H.M. of amplitude a and total energy E. At the instant its kinetic energy is $\frac{3E}{4}$ , its displacement y is given by

Q. A particle starts SHM from the mean position. Its amplitude is $A$ and total energy $E$. At an instant its kinetic energy is $\frac{3E}{4}$. Its displacement at this instant is

Q. When the displacement of a particle executing SHM is one - fourth of its amplitude, what fraction of the total energy is the kinetic energy?

Q. A particle is executing shm withh amplitude a and has maximum velocity $v_0$ .its speed at displacement $3a/4$ will be?