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Variation of G Due to Height and Depth

A body freely...

Question

A body freely falling from the rest has a velocity $^{'} v^{'}$ after it falls through a height $^{'} h^{'}$ . The distance it has to fall down for its velocity to become double, is

A

6 h

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B

4 h

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C

2 h

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D

8 h

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Solution

The correct option is B $4 h$
Let at point $A$ initial velocity of body is equal to zero
For path $A B :$
$v^{2} = 0 + 2 g h . . . . (i)$
For path $A C :$
$(2 v)^{2} = 0 + 2 g x$
$4 v^{2} = 2 g x . . . . (i i)$
Solving $(i)$ and $(i i)$ $x = 4 h$

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Variation of G Due to Height and Depth

Standard XII Physics

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