A body has an initial velocity of 4m/s and deceleration of 4m/s^{​​​​​2}​​​​​, then what is the final velocity after travelling 2m? [3 Marks]

Given:
u = 4 m/s
a = $-4m/s^2$
s = 2m

We know,
$v^2=u^2+2as$ [1 Mark]

=> $v^2=4^2+2\ast (-4)\ast 2$
$v^2=16-16$
$v^2=0$
v = 0 [2 Marks]

So, the final velocity is zero.