A body having specific charge 8 -C-g is resting on a frictionless plane at a distance 10 cm from the wall as shown in the figure- It starts moving towards the wall when a uniform electric field of 100 V-m is applied horizontally towards the wall- If the collision of the body with the wall is perfectly elastic- then the time period of the motion- in second will be -

Nbsp;F = ma ⇒ qE = ma ⇒ a =qEm Now, s=ut+12at^2 ⇒ d= nbsp;12 at^2=12qEmt^2 ⇒ t = nbsp;√(2mdqE) The time period of the motion of the block is given by, ...

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Byju's Answer

Standard XII

Physics

Infinite Sheet

A body having...

Question

A body having specific charge $8 ~\mu\text{C/g}$ is resting on a frictionless plane at a distance $10~\text{cm}$ from the wall (as shown in the figure). It starts moving towards the wall when a uniform electric field of $100~\text{V/m}$ is applied horizontally towards the wall. If the collision of the body with the wall is perfectly elastic, then the time period of the motion, in second will be ______.

Body 100 V/m

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Solution

$F = m a$

$\Rightarrow q E = m a$

$\Rightarrow a = \frac{q E}{m}$

Now,
$s = u t + \frac{1}{2} a t^{2}$

$\Rightarrow d = \frac{1}{2} a t^{2} = \frac{1}{2} \frac{q E}{m} t^{2}$

$\Rightarrow t = \sqrt{\frac{2 m d}{q E}}$

The time period of the motion of the block is given by,
$T = 2 t = 2 \times \sqrt{\frac{2 \times 0.1}{\frac{8 \times 10^{- 6}}{10^{- 3}} \times 100}} = 1 sec$

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