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Theoretical Verification of Law of Conservation

A body is dro...

Question

A body is dropped from the top of a tower. It acquires a velocity of $20 m s^{- 1}$ on reaching the ground. Calculate the height of the tower. (Take $g = 10 m s^{- 2}$ )

A

20 m

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B

10 m

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C

40 m

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D

30 m

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Solution

The correct option is A $20 m$
Final velocity , $v = 20 m / s$
$g = 10 m / s^{2}$
By third eqation of motion we have,
$v^{2} = u^{2} + 2 g S$
Since, $u = 0$
$S = \frac{v^{2}}{2 g}$
$\Rightarrow S = \frac{20^{2}}{2 \times 10} = 20 m$

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