A body is projected horizontally from the top of a tower with initial velocity $18m{s}^{-1}$. It hits the ground at angle ${45}^o$. What is the vertical component of velocity when it strikes the ground?

Q. A body is projected horizontally from the top of a tower with initial velocity 18 $m{s}^{-1}$. It hits the ground at angle ${45}^{\circ }$. What is the vertical component of velocity when it strikes the ground

Q. A body is projected horizontally from the top of a tower with an initial velocity of $18{\text{ms}}^{-1}$. It hits the ground at an angle of ${45}^{\circ }$ with horizontal. What is the vertical component of velocity when the body strikes the ground?

Q. A body is projected horizontally from the top of a tower with an initial velocity of $18{\text{ms}}^{-1}$. It hits the ground at an angle of ${45}^{\circ }$ with horizontal. What is the vertical component of velocity when the body strikes the ground?

Q. A body is projected horizontally from the top of a tower with a velocity of $10m/s$ . If it hits the ground at an angle of ${45}^o$ , the vertical component of velocity when it hits ground (in $m/s$) is:

Q. A body is projected horizontally from the top of tower. when the body strikes the ground its velocity is V and the direction of motion makes ${30}^o$ with the horizontal. the velocity of projection is: